For a periodic motion represented by the equation $Y=\sin \omega t+\cos \omega t$ The amplitude of the motion is
JEE MAIN 2023, Easy
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$y=\sin \omega t+\cos \omega t$
$y=\sin \omega t+\sin \left(\omega t+\frac{\pi}{2}\right)$
$\Delta \phi=\frac{\pi}{2}$
$A _{\text {net }}=\sqrt{1^2+1^2+2 \times 1 \times 1 \times \cos (\Delta \phi)}$
$A _{\text {met }}=\sqrt{2}$
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