MCQ
For a reaction whose rate expression is : Rate $ = k{[A]^{1/2}}{[B]^{3/2}}$, the order would be
- A$1.5$
- ✓$2$
- C$3$
- D$1$
$\therefore $ O.R. $= \frac{1}{2} + \frac{3}{2} = \frac{4}{2} = 2$
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In the above reaction $A, B$ and $C $ are the following compounds
$\begin{array}{*{20}{c}}
{C{H_3} - CH - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{\Delta }[Y]$
$[Y]$ will be :
$(I)\,\,CH_3CH_2OH + HCl \xrightarrow{{Anh.\,\,ZnC{l_2}}}$
$(II)\,\,CH_3CH_2OH + HCl \rightarrow$
$(III)\,\,(CH_3)_3COH + HCl \rightarrow$
$(IV)\,\,(CH_3)_2CHOH + HCl \xrightarrow{{Anh.\,\,ZnC{l_2}}}$