MCQ
For a single slit of width a, the first diffraction maximum with light of wavelength $\lambda$ subtends an angle $\theta$ such that $\sin \theta$ is equal to
- A$\frac{\lambda}{2 a}$
- B$\frac{\lambda}{a}$
- ✓$\frac{1.5 \lambda}{a}$
- D$\frac{2 \lambda}{a}$.