MCQ
For a single slit of width a, the first diffraction maximum with light of wavelength $\lambda$ subtends an angle $\theta$ such that $\sin \theta$ is equal to
  • A
    $\frac{\lambda}{2 a}$
  • B
    $\frac{\lambda}{a}$
  • $\frac{1.5 \lambda}{a}$
  • D
    $\frac{2 \lambda}{a}$.

Answer

Correct option: C.
$\frac{1.5 \lambda}{a}$
$\frac{1.5 \lambda}{\pi}$

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