MCQ
For a transistor, in a common emitter arrangement, the alternating current gain $b$ is given by
  • $\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}\right)_{\mathrm{VC}}$
  • B
    $\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{B}}}{\Delta \mathrm{I}_{\mathrm{C}}}\right)_{\mathrm{VC}}$
  • C
    $\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{E}}}\right)_{\mathrm{VC}}$
  • D
    $\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{E}}}{\Delta \mathrm{I}_{\mathrm{C}}}\right)_{\mathrm{VC}}$

Answer

Correct option: A.
$\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}\right)_{\mathrm{VC}}$
$\beta=\left(\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}\right)_{\mathrm{VC}}$

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