For a transistor, in a common emitter arrangement, the alternatin… - Vidyadip

MCQ

For a transistor, in a common emitter arrangement, the alternating current gain $\beta$ is given by

✓
$\beta = {\left( {\frac{{\Delta {I_C}}}{{\Delta {I_B}}}} \right)_{{V_C}}}$
B
$\beta = {\left( {\frac{{\Delta {I_B}}}{{\Delta {I_C}}}} \right)_{{V_C}}}$
C
$\beta = {\left( {\frac{{\Delta {I_C}}}{{\Delta {I_E}}}} \right)_{{V_C}}}$
D
$\beta = {\left( {\frac{{\Delta {I_E}}}{{\Delta {I_C}}}} \right)_{{V_C}}}$

✓

Answer

Correct option: A.

$\beta = {\left( {\frac{{\Delta {I_C}}}{{\Delta {I_B}}}} \right)_{{V_C}}}$

a
(a) $\beta=\frac{\Delta I_{c}}{\Delta I_{b}}$

Beta is the transistors forward current gain in the common emitter configuration. Beta has no units as it is a fixed ratio of the two currents, $I_{c}$ and $I_{b}$ so a small change in the Base current will cause a large change in the Collector current.

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