For a transverse wave travelling along a straight line, the distance between two peaks (crests) is $5 \,m ,$ while the distance between one crest and one trough is $1.5 \,m$ The possible wavelengths (in $m$ ) of the waves are
JEE MAIN 2020, Diffcult
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Given $T$ to $C\,\, 1.5 m$
$C$ to $C\, 5 m$
$T$ to $C =\left(2 n _{1}+1\right) \frac{\lambda}{2}$
$C$ to $C = n _{2} \lambda$
$\frac{1.5}{5}=\frac{\left(2 n _{1}+1\right)}{2 n _{2}} \Rightarrow 3 n _{2}=10 n _{1}+5$
$n _{1}=1, n _{2}=5 \rightarrow \lambda=1$
$n _{1}=4, n _{2}=15 \rightarrow \lambda=1 / 3$
$n _{1}=7, n _{2}=25 \rightarrow \lambda=1 / 5$
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