MCQ
For all real values of $\text{x},\cot\text{x}-2\cot\text{}$ is equal to:
- A$\tan2\text{x}$
- B$\tan\text{x}$
- C$-\cot3\text{x}$
- DNone of these
Solution:
We have,
$\cot\text{x}-2\cot2\text{x}=\cot\text{x}-2\frac{\cot^2\text{x}-1}{2\cot\text{x}}$
$=\frac{1}{\cot\text{x}}$
$=\tan\text{x}$
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