MCQ
For an electron if the uncertainty in velocity is $\Delta \nu $, the uncertainty in its position $(\Delta x)$ is given by
  • A
    $\frac{{hm}}{{4\pi \Delta \nu }}$
  • B
    $\frac{{4\pi }}{{hm\Delta \nu }}$
  • $\frac{h}{{4\pi m\Delta \nu }}$
  • D
    $\frac{{4\pi \;m}}{{h\;.\;\Delta \nu }}$

Answer

Correct option: C.
$\frac{h}{{4\pi m\Delta \nu }}$
c
According to the Heisenberg's uncertainty principle, it is impossible to determine simultaneously, the exact position and exact momentum (or velocity) of an electron.

$\Delta x . \triangle p _{ x }\, \geq\, \frac{ h }{4 \pi}$

$\Delta x \cdot m \Delta v\, \geq\, \frac{ h }{4 \pi}$

$\Delta x\, \geq \,\frac{ h }{4 \pi m \triangle v }$

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