For an electron, with n = 3 has only one radial node. The orbital… - Vidyadip

MCQ

For an electron, with $n = 3$ has only one radial node. The orbital angular momentum of the electron will be

A
$0$
B
$\sqrt 6 \frac{h}{{2\pi }}$
✓
$\sqrt 2 \frac{h}{{2\pi }}$
D
$ 3 (\frac{h}{{2\pi }})$

✓

Answer

Correct option: C.

$\sqrt 2 \frac{h}{{2\pi }}$

c
No. of radial nodes $=n-\ell-1=1$

$3-\ell-1=1$ $\therefore \ell=1$

Orbital angular momentum

$=\sqrt{\ell(\ell+1) \frac{\mathrm{h}}{2 \pi}}=\sqrt{2} \frac{\mathrm{h}}{2 \pi}$

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