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STD 11 - 3.2 , motion in plane — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 3.2 , motion in plane4 Marks
MCQ
For an object projected from ground with speed $u$ horizontal range is two times the maximum height attained by it. The horizontal range of object is ..........
  • A
    $\frac{2 u^2}{3 g}$
  • B
    $\frac{3 u^2}{4 g}$
  • C
    $\frac{3 u^2}{2 g}$
  • ✓
    $\frac{4 u^2}{5 g}$
✓

Answer

Correct option: D.
$\frac{4 u^2}{5 g}$
d
(d)

$R=24$ also,$\frac{H}{R}=\frac{1}{4} \tan \theta$

$\frac{H}{R}=\frac{1}{2} \Rightarrow \frac{1}{2}=\frac{1}{4} \tan \theta$

$\tan \theta=2=\frac{P}{B}$

$R=\frac{2 u^2 \sin \theta \cos \theta}{g}$

$R=\frac{2 u^2}{g} \cdot \frac{2}{\sqrt{5}} \times \frac{1}{\sqrt{5}}$

$R=\frac{4 u^2}{5 g}$

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