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Functions — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsFunctions1 Mark
Question
For any base show that $\log (1+2+3)=\log 1+\log 2+\log 3$
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Answer

$ \text { L.H.S. }=\log (1+2+3)=\log 6$
$\text { R.H.S. }=\log 1+\log 2+\log 3$
$=0+\log (2 \times 3)$
$=\log 6$
$\therefore \text { L.H.S. }=\text { R.H.S. }$

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