MCQ
For any given series of spectral lines of atomic hydrogen, let $\Delta \bar V\, = \,\Delta {\bar V_{\max }}\, - \,\Delta {\bar V_{\min }}$ be the difference in maximum and minimum frequencies in $cm^{-1}.$ the ration $\Delta {\bar V_{Lymann}}/\,\Delta {\bar V_{Balmer}}$ is
  • A
    $5:4$
  • B
    $4:1$
  • $9:4$
  • D
    $27:5$

Answer

Correct option: C.
$9:4$
c
$\Delta {{\bar V}_{Lymann}} = \frac{{{R_H}}}{4}$

$\Delta {{\bar V}_{Balmer}} = \frac{{{R_H}}}{9}$

$ \Rightarrow \frac{{\Delta {{\bar V}_{Lymann}}}}{{\Delta {{\bar V}_{Balmer}}}} = \frac{9}{4}$

Formula

$\bar V = {R_H}\left[ {\frac{1}{{n_1^2}} - \frac{1}{{n_2^{2}}}} \right]$

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