CBSE BoardEnglish MediumSTD 11 ScienceMathsModel Paper 91 Mark
MCQ
For any positive integer $n,(-\sqrt{-1})^{4 n+3}=$ ?
A
1
B
i
C
-i
D
-1
✓
Answer
(b) i Explanation: $(-\sqrt{-1})^{4 n+3}=(- i )^{4 n +3}=\left\{(- i )^4\right)^{ n }(-1)^3=1 \times(- i ) \times(- i ) \times(- i )= i ^2 \times(- i )=-1 \times(- i )= i$
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