MCQ
For any positive integer $n,(-\sqrt{-1})^{4 n+3}=$ ?
  • A
    1
  • B
    i
  • C
    -i
  • D
    -1

Answer

(b) i
Explanation: $(-\sqrt{-1})^{4 n+3}=(- i )^{4 n +3}=\left\{(- i )^4\right)^{ n }(-1)^3=1 \times(- i ) \times(- i ) \times(- i )= i ^2 \times(- i )=-1 \times(- i )= i$

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