MCQ
For any two non$-$zero rational numbers $a, \text{a}^7\div\text{a}^{12}$ is equal to:
  • A
    $\text{a}^5$
  • B
    $\text{a}^{-19}$
  • $\text{a}^{-5}$
  • D
    $\text{a}^{19}$

Answer

Correct option: C.
$\text{a}^{-5}$
$\text{a}^\text{m}\div\text{a}^\text{n}=\text{a}^{\text{m}-\text{n}}$
Hence,
$\text{a}^\text{7}\div\text{b}^{12}$
$=\text{a}^{7-12}$
$=\text{a}^{-5}$

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