- $\text{A}$
- $\text{B}$
- $\phi$
- $\text{A}\cap\text{B}.$
Solution:
$\text{A}\cap\text{(A}\cup\text{B)}'$
$=\text{A}\cap\text{(A}'\cup\text{B}')$ (De Morgen Law)
$=\text{(A}\cap\text{A}')\cap\text{B}'$
$=\phi\cap\text{B}'$
$=\phi$
Hence, the correct answer is option (c).
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Circle $M : x ^{2}+ y ^{2}=1$ ; Circle $N : x ^{2}+ y ^{2}-2 x =0$ ; Circle $O : x ^{2}+ y ^{2}-2 x -2 y +1=0$ ;Circle $P: x^{2}+y^{2}-2 y=0$
If the centre of circle $M$ is joined with centre of the circle $N$, further centre of circle $N$ is joined with centre of the circle $O ,$ centre of circle $O$ is joined with the centre of circle $P$ and lastly, centre of circle $P$ is joined with centre of circle $M ,$ then these lines form the sides of a