Download App

Sets — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsSets1 Mark
MCQ
For any two sets $A$ and $B, \text{A}\cap\text{(A}\cup\text{B)}'$ is equal to:
  • A
    $\text{A}$
  • B
    $\text{B}$
  • ✓
    $\phi$
  • D
    $\text{A}\cap\text{B}.$
✓

Answer

Correct option: C.
$\phi$
$\text{A}\cap\text{(A}\cup\text{B)}'$
$=\text{A}\cap\text{(A}'\cup\text{B}') ($De Morgen Law$)$
$=\text{(A}\cap\text{A}')\cap\text{B}'$
$=\phi\cap\text{B}'$
$=\phi$
Hence, the correct answer is option $(c).$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Sets→Sets — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

The locus of the point of intersection of the lines $\sqrt 3 x - y - 4\sqrt 3 k = 0$ and $\sqrt 3 kx + ky - 4\sqrt 3 = 0$ for different value of $k$ is
→
If $\mathop \sum \limits_{i = 1}^9 \left( {{x_i} - 5} \right) = 9$ and $\mathop \sum \limits_{i = 1}^9 {\left( {{x_i} - 5} \right)^2} = 45,$ then the standard deviation of the $9$ items  ${x_1},{x_2},\;.\;.\;.\;,{x_9}$ is :
→
For an ellipse $\frac{{{x^2}}}{9} + \frac{{{y^2}}}{4} = 1$ with vertices $A$  and $ A', $ tangent drawn at the point $P$  in the first quadrant meets the $y-$axis in $Q $ and the chord $ A'P$ meets the $y-$axis in $M.$  If $ 'O' $ is the origin then $OQ^2 - MQ^2$  equals to
→
Let $\alpha, \beta$ be the roots of the quadratic equation $x^2+\sqrt{6} x+3=0$. Then $\frac{\alpha^{23}+\beta^{23}+\alpha^{14}+\beta^{14}}{\alpha^{15}+\beta^{15}+\alpha^{10}+\beta^{10}}$ is equal to 
→
The set of all prime numbers is
→
Give the number of common tangents to circle ${x^2} + {y^2} + 2x + 8y - 23 = 0$ and ${x^2} + {y^2} - 4x - 10y + 9 = 0$
→
If $ - 1 + \sqrt { - 3} = r{e^{i\theta }},$then $\theta $ is equal to
→
The partial fractions of ${{{x^2} - 5} \over {{x^2} - 3x + 2}}$ are
→
$\cos40^\circ+\cos80^\circ+\cos160^\circ+\cos240=$
→
Let $z$ be a complex number satisfying $|z - 5i|\, \le 1$ such that amp $z$ is minimum. Then $z$ is equal to
→