MCQ
For $d-$ block elements the first ionization potential is of the order
- ✓$Zn > Fe > Cu > Cr$
- B$Sc = Ti < V = Cr$
- C$Zn < Cu < Ni < Co$
- D$V > Cr > Mn > Fe$
$Zn\,:\,1{s^2}\,2{s^2}\,{p^6}\,3{s^2}\,{p^6}\,{d^{10}}\,4{s^2}$
$Fe\,:\,1{s^2}\,2{s^2}\,{p^6}\,3{s^2}\,{p^6}\,{d^6}\,4{s^2}$
$Cu\,:\,1{s^2}\,2{s^2}\,{p^6}\,3{s^2}\,{p^6}\,{d^{10}}\,4{s^1}$
$Cr\,:\,1{s^2}\,2{s^2}\,{p^6}\,3{s^2}\,{p^6}\,{d^5}\,4{s^1}$
$IE_1$ follows the order $:\,Zn > Fe > Cu > Cr$
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$\lambda_{\mathrm{m}}^{0}\left(\mathrm{in}\; \mathrm{S} \;\mathrm{cm}^{2} \mathrm{mol}^{-1}\right)$ for $\mathrm{CH}_{3} \mathrm{COOH}$ will be