Question
For each inequality, determine which of the given numbers are in the solution set:
16 - 5 x ≤ - 4; 4, -3, 10.
16 - 5 x ≤ - 4; 4, -3, 10.
✓
Answer
If x = 4, then 16 - 5x = 16 - 5 x 4 = -4
Since, -4 ≤ - 4 is true.
So, x = 4 is in the solution of 16 - 5x - 4
If x = -3, then 16 - 5x = 16 - 5 x -3 = 31
Since, 31 ≤ - 4 is false.
So, x = -3 is not in the solution of 16 - 5x ≤ - 4
If x = 10, then 16 - 5x = 16 - 5 x 10 = -34
Since, -34 ≤ -4 is true.
So, x = 10 is in the solution of 16 - 5x ≤ -4.
Since, -4 ≤ - 4 is true.
So, x = 4 is in the solution of 16 - 5x - 4
If x = -3, then 16 - 5x = 16 - 5 x -3 = 31
Since, 31 ≤ - 4 is false.
So, x = -3 is not in the solution of 16 - 5x ≤ - 4
If x = 10, then 16 - 5x = 16 - 5 x 10 = -34
Since, -34 ≤ -4 is true.
So, x = 10 is in the solution of 16 - 5x ≤ -4.
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