Question
For each of the differential equations given in find the general solution:
$\frac{\text{dy}}{\text{dx}}+2\text{y}=\sin\text{x}$
$\frac{\text{dy}}{\text{dx}}+2\text{y}=\sin\text{x}$
The solution of the given differential equation is given by the relation,
$\text{y}(\text{I.F})=\int(\text{Q}\times\text{I.F})\text{dx}+\text{C}$ $\Rightarrow\ \text{ye}^{2\text{x}}=\int\sin\text{x}\cdot\text{e}^{2\text{x}}\text{dx}+\text{C}\ \ ....{(1)}$ $\text{Let}\ I=\int\sin\text{x}\cdot\text{e}^{2\text{x}}.$ $\Rightarrow\ I=\sin\text{x}\cdot\int\text{e}^{2\text{x}}\text{dx}-\int\bigg(\frac{\text{d}}{\text{dx}}(\sin\text{x})\cdot\int\text{e}^{2\text{x}}\text{dx}\bigg)\text{dx}$ $\Rightarrow\ I=\sin\text{x}\cdot\frac{\text{e}^{2\text{x}}}{2}-\int\bigg(\cos\text{x}\cdot\frac{\text{e}^{2\text{x}}}{2}\bigg)\text{dx}$ $\Rightarrow\ I=\frac{\text{e}^{2\text{x}}\sin\text{x}}{2}-\frac{1}{2}\bigg[\cos\text{x}\cdot\int\text{e}^{2\text{x}}-\int\bigg(\frac{\text{d}}{\text{dx}}(\cos\text{x})\cdot\int\text{e}^{2\text{x}}\text{dx}\bigg)\text{dx}\bigg]$ $\Rightarrow\ I=\frac{\text{e}^{2\text{x}}\sin\text{x}}{2}-\frac{1}{2}\bigg[\cos\text{x}\cdot\frac{\text{e}^{2\text{x}}}{2}-\int\bigg[(-\sin\text{x})\cdot\frac{\text{e}^{2\text{x}}}{2}\bigg]\text{dx}\bigg]$ $\Rightarrow\ I=\frac{\text{e}^{2\text{x}}\sin\text{x}}{2}-\frac{\text{e}^{2\text{x}}\cos\text{x}}{4}-\frac{1}{4}\int\big(\sin\text{x}.\text{e}^{2\text{x}}\big)\text{dx}$ $\Rightarrow\ I=\frac{\text{e}^{2\text{x}}}{4}(2\sin\text{x}-\cos\text{x})-\frac{1}{4}I$ $\Rightarrow\ \frac{5}{4}I=\frac{\text{e}^{2\text{x}}}{4}(2\sin\text{x}-\cos\text{x})$ $\Rightarrow\ I=\frac{\text{e}^{2\text{x}}}{5}(2\sin\text{x}-\cos\text{x})$ Therefore, equation (1) becomes: $\text{y}^{2\text{x}}=\frac{\text{e}^{2\text{x}}}{5}(2\sin\text{x}-\cos\text{x})+\text{C}$ $\Rightarrow\ \text{y}=\frac{1}{5}(2\sin\text{x}-\cos\text{x})+\text{C}\text{e}^{-2\text{x}}$ This is the required general solution of the given differential equation.Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.