MCQ
For frictionless surfaces in given arrangement tension $T_2$ is :-
- ✓$mg/3$
- B$2\,mg/3$
- C$3\,mg/2$
- D$5\,mg/3$
✓
Answer
Correct option: A.
$mg/3$
a
$a=\frac{2 m g}{m+2 m+3 m}=\frac{g}{3}$
$a=\frac{2 m g}{m+2 m+3 m}=\frac{g}{3}$
$\mathrm{T}_{2}=\mathrm{m} \times \mathrm{a}=\mathrm{m} \times \mathrm{g} / 3$
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