MCQ
For given systen ${\theta _2}$ ....... $^o$
- A$30^o$
- B$45^o$
- C$60^o$
- ✓${\tan ^{ - 1}}\left( {\frac{1}{2}} \right)$
✓
Answer
Correct option: D.
${\tan ^{ - 1}}\left( {\frac{1}{2}} \right)$
d
$\frac{{\sin {\theta _2}}}{{\cos {\theta _2}}} = \frac{{mg}}{{2mg}}$$ \Rightarrow $ $\tan {\theta _2} = \frac{1}{2}$
$\frac{{\sin {\theta _2}}}{{\cos {\theta _2}}} = \frac{{mg}}{{2mg}}$$ \Rightarrow $ $\tan {\theta _2} = \frac{1}{2}$
$\therefore {\theta _2} = {\tan ^{ - 1}}\left[ {\frac{1}{2}} \right]$
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