$\mathrm{X}_{\mathrm{A}}$ decreases, $\therefore$ Solute increases
$\uparrow \Delta \mathrm{T}_{\mathrm{b}}=\mathrm{m} \uparrow \mathrm{k}_{\mathrm{b}}$
$\uparrow \Delta \mathrm{T}_{\mathrm{f}}=\uparrow \mathrm{m} \mathrm{k}_{\mathrm{f}}$
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$(I)$ $\begin{array}{*{20}{c}}
{C{H_2} - C{H_2} - C{H_2} - C{H_2}OH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{N{O_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$(II)$ $\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - CH - C{H_2}OH} \\
{|\,} \\
{N{O_2}}
\end{array}$
$(III)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - C{H_2}OH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{N{O_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$(IV)$ $CH_3-CH_2-CH_2-CH_2OH$
Select answer from codes given below :
$(1)$ $\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\, \\
{{H}_{3}}C-C-C{{H}_{2}}-Cl \\
\end{matrix}$
$(2)$ ${{H}_{2}}C-C{{H}_{2}}-C{{H}_{2}}-Cl$
$(3)$ ${{({{H}_{3}}C)}_{3}}C-Cl$