MCQ
For matrix $A=\left[\begin{array}{cc}2 & 5 \\ -11 & 7\end{array}\right],(\operatorname{adj} A)^{\prime}$ is equal to
  • A
    $\left[\begin{array}{ll}-2 & -5 \\ 11 & -7\end{array}\right]$
  • B
    $\left[\begin{array}{cc}7 & 5 \\ 11 & 2\end{array}\right]$
  • C
    $\left[\begin{array}{cc}7 & 11 \\ -5 & 2\end{array}\right]$
  • D
    $\left[\begin{array}{cc}7 & -5 \\ 11 & 2\end{array}\right]$

Answer

We know that, $(\operatorname{adj} A)^{\prime}=$ cofactor matrix of $A$
Here, cofactor matrix of $A=\left[\begin{array}{cc}7 & 11 \\ -5 & 2\end{array}\right]=(\operatorname{adj} A)^{\prime}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If A and B are two matrices of order 3×m and 3×n respectively and m = n, then the order of 5A - 2B is:
  1. m×3
  2. 3×3
  3. m×n
  4. 3×n
Let $\overrightarrow{ a }=\hat{ i }+2 \hat{ j }-\hat{ k }, \overrightarrow{ b }=\hat{ i }-\hat{ j }$ and $\overrightarrow{ c }=\hat{ i }-\hat{ j }-\hat{ k }$ be three given vectors. If $\overrightarrow{ r }$ is a vector such that $\overrightarrow{ r } \times \overrightarrow{ a }=\overrightarrow{ c } \times \overrightarrow{ a }$ and $\overrightarrow{ r } \cdot \overrightarrow{ b }=0,$ then $\overrightarrow{ r } \cdot \overrightarrow{ a } \quad$ is equal to ...........
The area bounded by the curve y = 4x - x2 and the x-axis is:
  1. $\frac{30}{7}\text{ sq. units}$
  2. $\frac{31}{7}\text{ sq. units}$
  3. $\frac{32}{3}\text{ sq. units}$
  4. $\frac{34}{3}\text{ sq. units}$
$\int\limits_0^{^n{C_r}} {\{ {{\sin }^2}\{ x\} \} dx} $ is equal to $($ where $\{.\}$ denotes fractional part function & $n, r  \in  N$ $)$
Let $\overrightarrow{ a }=\alpha \hat{ i }+2 \hat{ j }-\hat{ k }$ and $\overrightarrow{ b }=-2 \hat{ i }+\alpha \hat{ j }+\hat{ k }$, where $\alpha \in R$. If the area of the parallelogram whose adjacent sides are represented by the vectors $\vec{a}$ and $\vec{b}$ is $\sqrt{15\left(\alpha^{2}+4\right)}$, then the value of $2|\vec{a}|^{2}+(\vec{a} \cdot \vec{b})|\vec{b}|^{2}$ is equal to
The maximum value of $\sin x\,\,(1 + \cos x)$ will be at the
$\int\frac{\cos2\text{x}-\cos2\theta}{\cos\text{x}-\cos\theta}\text{dx}$  is equal to:
  1. $2(\sin\text{x}+\text{x}\cos\theta)+\text{c}$
  2. $2(\sin\text{x}-\text{x}\cos\theta)+\text{c}$
  3. $2(\sin\text{x}+2\text{x}\cos\theta)+\text{c}$
  4. $2(\sin\text{x}-2\text{x}\cos\theta)+\text{c}$
$\tan \left[ {{{\sec }^{ - 1}}\sqrt {1 + {x^2}} } \right] = $
If x < 0, y < 0 such that xy = 1, then $\tan^{-1}\text{x}+\tan^{-1}\text{y}$ equals:
  1. $\frac{\pi}{2}$
  2. $-\frac{\pi}{2}$
  3. $-\pi$
  4. $\text{none of these}$
Let $a-2 b+c=1$

If $f(x)=\left|\begin{array}{lll}{x+a} & {x+2} & {x+1} \\ {x+b} & {x+3} & {x+2} \\ {x+c} & {x+4} & {x+3}\end{array}\right|,$ then