MCQ
For net primary productivity energy captured is
- A$1 -5\;\ %$ of incident radiation
- B$2 -5\;\%$ of $PAR$
- ✓$0.8 -4\;\%$ of incident radiation
- D$2 -10\;\%$ of $PAR$
✓
Answer
Correct option: C.
$0.8 -4\;\%$ of incident radiation
c
$0.8 -4\;\% $ of incident radiation for net primary productivity.
$0.8 -4\;\% $ of incident radiation for net primary productivity.
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