MCQ
For regular pentagon system shown in figure, find force on $q_0$
  • $\frac{{KQ{q_0}}}{{{x^2}}}$
  • B
    $\frac{{2KQ{q_0}}}{{{x^2}}}$
  • C
    $\frac{{KQ{q_0}}}{{{2x^2}}}$
  • D
    zero

Answer

Correct option: A.
$\frac{{KQ{q_0}}}{{{x^2}}}$
a
force on  ${\rm{'}}{{\rm{q}}_0}'$

$\Rightarrow \mathrm{F}=\frac{\mathrm{KQ} \mathrm{q}_{0}}{\mathrm{x}^{2}}$

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