MCQ
For same order square matrix $A , B , C , AB = AC$ $\Rightarrow B=C$, then $A$ will be :
  • A
    Non-invertible matrix
  • B
    Non-zero matrix
  • C
    Unit matrix
  • Invertible matrix.

Answer

Correct option: D.
Invertible matrix.
(D)
Because in invertible matrix $|A| \neq 0$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Integrating factor of differential equation $\frac{d y}{d x}+y \tan x-\sec x=0$ is
The matrix $\left( {\begin{array}{*{20}{c}}1&a&2\\1&2&5\\2&1&1\end{array}} \right)$ is not invertible, if  $‘a’ $ has the value
Function $f(x) = {{\lambda \sin x + 6\cos x} \over {2\sin x + 3\cos x}}$ is monotonic increasing, if
If $\vec w = \alpha \left( {\vec a \times \vec b} \right) + \beta \left( {\vec b \times \vec c} \right) + \gamma \left( {\vec c \times \vec a} \right),$ $\left[ {\vec a,\vec b,\vec c} \right] = 2$ and $\vec w.\left( {\vec a + \vec b + \vec c} \right) = 8$, then $\alpha  + \beta  + \gamma  =$
Let $h(x)=$ $\frac{{5{{(f(x))}^3}}}{3} + \frac{{{{(f(x))}^2}}}{2} + 2f(x)+ 100$ Where $f(x)$ is a differentiable function. Then which one of the following is correct
Let $f(x + y) = f(x) + f(y)$and $f(x) = {x^2}g(x)$ for all $x,y \in R$, where $g(x)$ is continuous function. Then $f'(x)$ is equal to
Find the area of bounded by $\text{y}=\sin\text{x}$  from $\text{x}=\frac{\pi}{4}$ to $\text{x}=\frac{\pi}{2}:$
  1. $\frac{\sqrt{2-1}}{\sqrt2}$
  2. $\frac{1}{2}$
  3. $\frac{1}{4}$
  4. $\text{none}\text{ of}\text{ these}$
The differential equation $\frac{d y}{d x}=F(x, y)$ will not be a homogeneous differential equation, if $F(x, y)$ is:
The solution of the differention equation $\frac{\text{dy}}{\text{dx}}=\frac{\text{x}^{2}+\text{xy}+\text{y}^{2}}{\text{x}^{2}}$ is:
  1. $\tan^{-1}\big(\frac{\text{x}}{\text{y}}\big)-\log\text{y}+\text{C}$ 
  2. $\tan^{-1}\big(\frac{\text{y}}{\text{x}}\big)-\log\text{x}+\text{C}$
  3. $\tan^{-1}\big(\frac{\text{x}}{\text{y}}\big)=\log\text{x}+\text{C}$
  4. $\tan^{-1}\big(\frac{\text{y}}{\text{x}}\big)=\log\text{y}+\text{C}$
The solution of the differential equation $x\sec y\frac{{dy}}{{dx}} = 1$ is