Question
For the $\beta^{+}$ (positron) emission from a nucleus, there is another competing process known as electron capture (electron from an inner orbit, say, the K–shell, is captured by the nucleus and a neutrino is emitted).
$\text{e}^{+}+^{\text{A}}_{\text{Z}}\text{X}\rightarrow\ ^{\text{A}}_{\text{Z}-1}\text{Y}+\text{v}$
Show that if $\beta^{+}$ emission is energetically allowed, electron capture is necessarily allowed but not vice–versa.

Answer

Let the amount of energy released during the electron capture process be $Q_1.$ The nuclear reaction can be written as:
$\text{e}^{+}+^{\text{A}}_{\text{Z}}\text{X}\rightarrow^{\text{A}}_{\text{Z}-1}\text{Y}+\text{v}+\text{Q}_1\ \dots(1)$
Let the amount of energy released during the positron capture process be $Q_2.$ The nuclear reaction can be written as:
$^{\text{A}}_{\text{Z}}\text{X}\rightarrow^{\text{A}}_{\text{Z}-1}\text{Y}+\text{e}^{+}+\text{v}+\text{Q}_2\ \dots(2)$
$\text{m}_\text{N}(^{\text{A}}_{\text{Z}}\text{X})$ = Nuclear mass of $^{\text{A}}_{\text{Z}}\text{X}$
$\text{m}_\text{N}(_{\text{Z}-1}^\text{A}\text{Y})$ = Nuclear mass of $_{\text{Z}-1}^{\text{A}}\text{Y}$
$\text{m}(^{\text{A}}_{\text{Z}}\text{X})$ = Atomic mass of $^\text{A}_\text{Z}\text{X}$
$\text{m}(^{\text{A}}_{\text{Z}-1}\text{Y})$ = Atomic mass of $^{\text{A}}_{\text{Z}-1}\text{Y}$
$m_e =$ Mass of an electron
$c =$ Speed of light
Q-value of the electron capture reaction is given as:
$\text{Q}_1=\Big[\text{m}_{\text{N}}(^{\text{A}}_{\text{Z}}\text{X})+\text{m}_{\text{e}}-\text{m}_{\text{N}}(^{\text{A}}_{\text{Z}-1}\text{Y})\Big]\text{c}^2$
$=\Big[\text{m}(^{\text{A}}_{\text{Z}}\text{X})-\text{Zm}_\text{e}+\text{m}_\text{e}-\text{m}(^{\text{A}}_{\text{Z}-1}\text{Y})+(\text{Z}-1)\text{m}_\text{e}\Big]\text{c}^2$
$=\Big[\text{m}(^{\text{A}}_{\text{Z}}\text{X})-\text{m}(^{\text{A}}_{\text{Z}-1}\text{Y})\Big]\text{c}^2$
Q-value of the positron capture reaction is given as:
$\text{Q}_2=\Big[\text{m}_{\text{N}}(^{\text{A}}_{\text{Z}}\text{X})-\text{m}_{\text{N}}(^{\text{A}}_{\text{Z}-1}\text{Y})-\text{m}_\text{e}\Big]\text{c}^2$
$=\Big[\text{m}(^{\text{A}}_{\text{Z}}\text{X})-\text{Zm}_\text{e}-\text{m}(^{\text{A}}_{\text{Z}-1}\text{Y})+(\text{Z}-1)\text{m}_\text{e}-\text{m}_\text{e}\Big]\text{c}^2$
$=\Big[\text{m}(^{\text{A}}_{\text{Z}}\text{X})-\text{m}(^{\text{A}}_{\text{Z}-1}\text{Y})-2\text{m}_\text{e}\Big]\text{c}^2$
It can be inferred that if $Q_2 > 0,$ then Q_1 > 0; Also, if $Q_1 > 0,$ it does not necessarily mean that $Q_2 > 0.$

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