Question
For the circuit shown below, the current through the Zener diode is......$mA$
✓
Answer
$\mathrm{I}_{10 \mathrm{k}}=\frac{50}{10 \mathrm{k}}=5\, \mathrm{mA}$
$\mathrm{i}_{5 \mathrm{k}}=\frac{120-50}{5 \mathrm{k}}=14\, \mathrm{mA}$
$\mathrm{i}_{2}=(14-5) \mathrm{mA}=9\, \mathrm{mA}$
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