Question
For the circuit shown in the figure, the current $I$ will be .......$A$
✓
Answer
c
By KVL in a closed loop ABCDA,
By KVL in a closed loop ABCDA,
$V_{A}-1 \times 4-1 \times 1+4-1 \times 1+2=V_{A}$
$-61+6=0$
$1=1 A$
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