Question
For the determination of ‘g’ using a simple pendulum, measurements of I and T are required. Error in the measurement of which of these will have larger effect on the value of 'g' thus obtained and why? What is done to minimize this error?
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Answer
Error in measurement of time period T has larger effect on the value of g. Since $\text{T}=2\pi\sqrt{\frac{\text{l}}{\text{g}}}\Rightarrow\text{g}=\frac{\text{l}}{\text{T}^2}$ Thus, time for large number ofoscillations is measured to minimise error.
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