MCQ
For the ellipse $\frac{{{x^2}}}{{64}} + \frac{{{y^2}}}{{28}} = 1$, the eccentricity is
  • $\frac{3}{4}$
  • B
    $\frac{4}{3}$
  • C
    $\frac{2}{{\sqrt 7 }}$
  • D
    $1\over3$

Answer

Correct option: A.
$\frac{3}{4}$
a
(a) ${e^2} = 1 - \frac{{{b^2}}}{{{a^2}}}$

${e^2} = \frac{{36}}{{64}}$

==> $e = \frac{3}{4}$.

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