Question
For the equation given below, find the slope and the $y-$intercept$:3x - y - 8 = 0$
✓
Answer
Equation of any straight line in the form $y = mx + c,$ where slope $= m($co$-$efficient of $x)$ and $y-$intercept $= c($constant term$)$
$3x - y - 8 = 0$
$3x - y - 8 = 0$
$- y = - 3x + 8$
$y = 3x + (- 8)$
Therefore,
slope $=$ co$-$efficient of $x = 3$
$y-$intercept $=$ constant term $= - 8.$
$3x - y - 8 = 0$
$3x - y - 8 = 0$
$- y = - 3x + 8$
$y = 3x + (- 8)$
Therefore,
slope $=$ co$-$efficient of $x = 3$
$y-$intercept $=$ constant term $= - 8.$
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