For the following distribution, calculate mean using all suitable… - Vidyadip

Question

For the following distribution, calculate mean using all suitable methods.

Size of item	$1-4$	$4-9$	$9-16$	$16-27$
Frequency	$6$	$12$	$26$	$20$

✓

Answer

Let assumed mean $(A) = 12.5$

Size of item	Class Marks $(x)$	Frequency $(f)$	$d_i = x - A A = 12.5$	$f_id_i$
1-4	2.5	6	-10	-60
4-9	6.5	12	-6	-72
9-16	12.5 - A	26	0	0
16-27	21.5	20	9	180
Total		64		48

$\text{Mean}=\text{A}+\text{hx}\frac{\sum\text{f}_\text{i}\text{d}_\text{i}}{\sum\text{f}_\text{i}}=12.5+\frac{48}{64}$
$=12.5+\frac{3}{4}=12.5+0.75=13.25$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "3 Marks Question" from Statistics→Statistics — all question types→Maths STD 10 question papers→Maharashtra Board STD 10 question papers→Maharashtra Board question paper generator→

Similar questions

In the given figure, $\triangle\text{ABC}$ is right angled at C and $\text{DE}\perp\text{AB.}$ Prove that $\triangle\text{ABC}\sim\triangle\text{ADE}$ and hence find the length of AE and DE.

Show that the points (-3, 2), (-5, -5), (2, -3) and (4, 4) are the vertices of a rhombus. Find the area of this rhombus.

How many numbers of two digit are divisible by $3$?

If the $10^{th}$ term of an AP is $52$ and $17^{th}$ term is $20$ more than its $13^{th}$ term, find the AP.

Draw a circle of radius 3.3 cm Draw a chord PQ of length 6.6 cm. Draw tangents to the circle at points P and Q. Write your observation about the tangents.

Find the eighteenth term of the A.P. 1, 7, 13, 19.

In the given figure, XY || BC. Find the length of XY.

$\sqrt{\frac{1-\cos\text{A}}{1+\cos\text{A}}}+\sqrt{\frac{1+\cos\text{A}}{1-\cos\text{A}}}=2\text{cosec }\text{A}$

If a $\triangle\text{ABC},$ AD is the bisector of $\angle\text{A},$ Meeting side BC at D.
If AB = 3.5cm, AC = 4.2cm and DC = 2.8cm, find BD.

In three line segments OA, OB, and OC, points L, M, N respectively are so chosen that LM || AB and MN || BC but neither of L, M, N nor of A, B, C are collinear. Show that LN || AC.