MCQ
For the function $f(x) = {e^x},a = 0,b = 1$, the value of $ c$ in mean value theorem will be
- A$log \,x$
- ✓$\log (e - 1)$
- C$0$
- D$1$
==> $\frac{{{e^b} - {e^a}}}{{b - a}} = f'(c)$
==>$\frac{{e - 1}}{{1 - 0}} = {e^c} \Rightarrow c = \log (e - 1)$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$[A]$ $e^x-\int_0^x f(t) \sin t d t$ $[B]$ $x^9-f(x)$ $[C]$ $f(x)+\int_0^{\pi / 2} f(t) \sin t d t$
$[D]$ $x-\int_0^{\frac{\pi}{2}-x} f(t) \cos t d t$