For the function y = x^2, if x = 10 and =0.1. Find . - Vidyadip

Question

For the function $y = x^2$, if $x = 10$ and $\triangle\text{x}=0.1$. Find $\triangle\text{y}.$

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Answer

$\text{y}=\text{x}^2$
$\triangle\text{x}=0.1$
$\text{x}=10$
$\frac{\text{dy}}{\text{dx}}=2\text{x}$
$\Rightarrow\Big(\frac{\text{dy}}{\text{dx}}\Big)_{\text{x}=10}=20$
$\Rightarrow\triangle\text{y}=\text{dy}=\frac{\text{dy}}{\text{dx}}\text{dx}=20\times0.1=2$

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