${A_2}\left( g \right) + {B_2}\left( g \right) \rightleftharpoons 2AB\left( g \right)$
${\Delta _r}{G^o}$ and ${\Delta _r}{S^o}$ are $20\, kJ/mol$ and $-20\, JK^{-1}\, mol^{-1}$ respectively at $200\, K$.
If ${\Delta _r}{C_P}$ is $20\, JK^{-1}\, mol^{-1}$ then ${\Delta _r}{H^o}$ at $400\, K$ is.....$kJ/mol$
$\Delta \mathrm{H}_{2 \mathrm{0} 0}^{\circ}=20-4=16\, \mathrm{kJ} / \mathrm{mol}$
$\Delta \mathrm{H}_{\mathrm{T}_{2}}^{\circ}=\Delta \mathrm{H}_{\mathrm{T}_{1}}^{\circ}+\Delta \mathrm{C}_{\mathrm{P}}\left[\mathrm{T}_{2}-\mathrm{T}_{1}\right]$
$\Delta \mathrm{H}_{400}^{\circ}=\Delta \mathrm{H}_{200}^{\circ}+\frac{20 \times 200}{1000} \,\mathrm{kJ} / \mathrm{mol}$
$=16+4=20 \,\mathrm{kJ} / \mathrm{mole}$
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