MCQ
For the logic circuit shown, the truth table is :
- A$\begin{array}{lll}\text {A} & \text {B} & \text {Y} \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 0\end{array}$
- ✓$\begin{array}{lll}\text {A} & \text {B} & \text {Y} \\ 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{array}$
- C$\begin{array}{lll}\text {A} & \text {B} & \text {Y} \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1\end{array}$
- D$\begin{array}{lll}\text {A} & \text {B} & \text {Y} \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0\end{array}$