MCQ
For the reaction, $\text{CO(g)}+\text{ClO}_2\text{(g)}\rightleftharpoons\text{COCl}_2(\text{g}),$ the $\frac{\text{K}_{\text{p}}}{\text{K}_\text{C}}$ is equal to:
- A$\sqrt{\text{RT}}$
- B$\text{RT}$
- C$\frac{1}{\text{R.T}}$
- D$1.0$
✓
Answer
- $\frac{1}{\text{R.T}}$
Explanation:
$\text{K}_{\text{p}}=\text{K}_{\text{C}}(\text{RT})^{\Delta\text{n}}$
$\Rightarrow\text{K}_{\text{p}}=\text{K}_{\text{C}}(\text{RT})^{1-2}$
$\Rightarrow\frac{\text{K}_{\text{p}}}{\text{K}_{\text{C}}}=\frac{1}{\text{RT}}$
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