MCQ
For the reaction ${N_2} + 3{H_2}$ $\rightleftharpoons$ $2N{H_3};\,\Delta H = ?$
- A$\Delta E - RT$
- ✓$\Delta E - 2RT$
- C$\Delta E + RT$
- D$\Delta E + 2RT$
✓
Answer
Correct option: B.
$\Delta E - 2RT$
(b)$\Delta H = \Delta E + \Delta nRT$
Since $\Delta n = - 2$
Than $\Delta H = \Delta E - 2RT$.
Since $\Delta n = - 2$
Than $\Delta H = \Delta E - 2RT$.
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