MCQ
For the reaction, $\text{N}_2(\text{g})+3\text{H}_2(\text{g})\rightleftharpoons2\text{NH}_3(\text{g});\ \Delta\text{H}$ is:
- A
- B
- C
- D
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$N_2(g) + 3H_2(g) \to 2NH_3(g)$ is
$-\,92.38\,KJ$ at $298\,K$ . The internal energy change $\Delta U$ at $298\,K$ is.....$KJ$