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Haloalkanes and Haloarenes — Chemistry STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 ScienceChemistryHaloalkanes and Haloarenes1 Mark
Question
For the reaction, the major product is formed by:
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Answer

Since, $\ce{CH_3​CH_2​O}$ is a moderate base, so there is no possibility of $E_1$​ reaction and in $E_{1\ CB}​,$ there takes place the carbanion formation. Hex, there is no anion stabilising group, so $E_{1​\ CB}$ is not possible.$E.$ mechanism is possible because of presence of $H -$atom anti to the leaving group $(Br).$

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