MCQ
For the reaction, the major product is formed by: 
- AAn $E_1$ reaction
- ✓An $E_2$ reaction
- C$S_{N_1}$ reaction
- D$S_{N_2}$ reaction
✓
Answer
Correct option: B.
An $E_2$ reaction
Since$, \ce{CH_3CH_2O}$ is a moderate base, so there is no possibility of $E_1$ reaction and in $\ce{E_1CB}$, there takes place the carbanion formation. Hex, there is no anion stabilising group, so $\ce{E_1CB}$ is not possible.
$E.$ mechanism is possible because of presence of $H -$atom anti to the leaving group $(Br).$
$E.$ mechanism is possible because of presence of $H -$atom anti to the leaving group $(Br).$
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