MCQ
For the reactions

$A\, \rightleftharpoons \,B$                     ${K_C} = 2$

$B\, \rightleftharpoons \,C$                    ${K_C} = 3$

$C\, \rightleftharpoons \,D+E$               ${K_C} = 5$

$K_C$ for the reaction $A\, \rightleftharpoons \,D+E$ is

  • A
    $2 + 3 + 5$
  • B
    $\frac{{2 \times 3}}{5}$
  • C
    $\frac{{5 \times 3}}{2}$
  • $2 \times 3 \times 5$

Answer

Correct option: D.
$2 \times 3 \times 5$
d
By adding all the three reactions, we will get target reaction. On adding reaction, there equilibrium constant will be multiplled

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