$A\, \rightleftharpoons \,B$ ${K_C} = 2$
$B\, \rightleftharpoons \,C$ ${K_C} = 3$
$C\, \rightleftharpoons \,D+E$ ${K_C} = 5$
$K_C$ for the reaction $A\, \rightleftharpoons \,D+E$ is
- A$2 + 3 + 5$
- B$\frac{{2 \times 3}}{5}$
- C$\frac{{5 \times 3}}{2}$
- ✓$2 \times 3 \times 5$