Download App

MARCH 2024 — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsMARCH 20241 Mark
MCQ
For vectors $\bar{a}$ and $\bar{b},|\bar{a}|=\frac{2}{3},|\bar{b}|=3$ and $|\bar{a} \times \bar{b}|=1$, then, angle between $\bar{a}$ and $\bar{b}$ is ___________.
  • ✓
    $\frac{\pi}{6}$
  • B
    $\frac{\pi}{4}$
  • C
    $\frac{\pi}{3}$
  • D
    $\frac{\pi}{2}$
✓

Answer

Correct option: A.
$\frac{\pi}{6}$
A

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from MARCH 2024→MARCH 2024 — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

If $f(x) = \left\{ \begin{array}{l}x\frac{{{e^{(1/x)}} - {e^{( - 1/x)}}}}{{{e^{(1/x)}} + {e^{( - 1/x)}}}},\,x \ne 0\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,\,x = 0\end{array} \right.$ then which of the following is true
→
If $\left| {\,\begin{array}{*{20}{c}}{3x - 8}&3&3\\3&{3x - 8}&3\\3&3&{3x - 8}\end{array}\,} \right| = 0,$ then the values of $x$ are
→
If the function $f(x)=\left\{\begin{array}{cc}(1+|\cos x|) \frac{\lambda}{|\cos x|} & , 0 < x < \frac{\pi}{2} \\ \mu & , x=\frac{\pi}{2} \\ e^{\frac{\cot 6 x}{\cot 4 x }} & , \frac{\pi}{2} < x < \pi\end{array}\right.$ is continuous at $x =\frac{\pi}{2}$, then $9 \lambda+6 \log _{ e } \mu+\mu^6- e ^{6 \lambda}$ is equal to
→
Curve passing through $(3, 0)$ and satisfying the differential equation $\left( {9 - {x^2}} \right){\left( {\frac{{dy}}{{dx}}} \right)^2} = 9 - {y^2}$ represents
→
The magnitude of each of the two vectors $\vec{a}$ and $\vec{b}$, having the same magnitude such that the angle between them is $60^{\circ}$ and their scalar product is $\frac{9}{2}$, is
→
If ${e^{f(x)}} = \frac{{10 + x}}{{10 - x}},\;x \in ( - 10,\;10)$ and $f(x) = kf\left( {\frac{{200x}}{{100 + {x^2}}}} \right)$, then $k = $
→
The value of the integral $\int_0^{\pi / 2} \frac{3 \sqrt{\cos \theta}}{(\sqrt{\cos \theta}+\sqrt{\sin \theta})^5} d \theta$ equals
→
If $\int\frac{\sin^8\text{x}-\cos^8\text{x}}{1-2\sin^2\text{x}\cos^2\text{x}}\text{ dx}=\text{a}\sin2\text{x}+\text{C},$ then a =
  1. $-\frac{1}{2}$
  2. $\frac{1}{2}$
  3. $-1$
  4. $1$
→
Given $P\left( x \right) = {x^4} + a{x^3} + b{x^2} + cx + d$ such that $x=0 $ is the only real root of  $P'\left( x \right) = 0$ . If  $P(-1) < P(1)$ ,then in the interval $[-1,1]$
→
The differential equation of all parabolas whose axes are parallel to y-axis is:
  1. $\frac{\text{dy}}{\text{dx}}=-\frac{\text{c}^2}{\text{x}^2}$
  2. $\frac{\text{d}^2\text{x}}{\text{dy}^2}=\text{c}$
  3. $\frac{\text{d}^3\text{y}}{\text{dx}^3}+\frac{\text{d}^2\text{x}}{\text{dy}^2}=0$
  4. $\frac{\text{d}^2\text{y}}{\text{dx}^2}+2\frac{\text{dy}}{\text{dx}}=0$
→