MCQ
For which of the following is $m = 8?$
- ✓$\frac{\Big(5^{\text{m}}-5^{-3}\Big)}{5^2=5^3}$
- B$\frac{\Big(5^{\text{m}}-5^{-3}\Big)}{5^3=5^2}$
- C$\frac{\Big(5^{\text{m}}-5^{3}\Big)}{5^2=5^3}$
- D$\frac{\Big(5-5^{-2}\Big)}{5^2=5^3}$
$\text{m}=8$
$=\frac{5^2-5^{-3}}{5^2}=5^3$
$=\frac{5^{[8+(-3)]}}{5^2}$
$=\frac{5^5}{5^2}$
$=5^3=5^3$
Hence Prove.
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