MCQ
For which value of $k$, this funciton is continuous at $x=1$.$
f(x)=\left\{\begin{array}{cc}
\frac{x^2-3 x+2}{x-1}, & x \neq 1 \\
k, & x=1
\end{array}\right.
$
  • A
    1
  • -1
  • C
    $0$
  • D
    3

Answer

Correct option: B.
-1
(B)
value of function at $x=1$
f(1)=k
Value of R.H.L.
$\lim _{h \rightarrow 0} f(1+h)=\lim _{h \rightarrow 0} \frac{(1+h)^2-3(1+h)+2}{1+h-1}$
$\begin{array}{l}=\lim _{h \rightarrow 0} \frac{1+2 h+h^2-3-3 h+2}{h} \\ =\lim _{h \rightarrow 0} \frac{h^2-h}{h}=\lim _{h \rightarrow 0}[h-1]=-1\end{array}$
because function is continuous at $x=1$, so
$\begin{array}{l}f(1)= R . H . L . \\ \therefore k=-1\end{array}$
Hence correct option is (B).

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