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4.1 , newtons laws of motion — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics4.1 , newtons laws of motion1 Mark
MCQ
Force acts for $20\,s$ on a body of mass $20\,kg$, starting from rest, after which the force ceases and then body describes $50\,m$ in the next $10\,s$. The value of force will be $..........\,N$
  • A
    $40$
  • ✓
    $5$
  • C
    $20$
  • D
    $10$
✓

Answer

Correct option: B.
$5$
b
$50= V \times 10$

$V =5\,m / s$

$V =0+ a \times 20$

$5= a \times 20$

$a =\frac{1}{4}\,m / s ^2$

$F = ma =20 \times \frac{1}{4}=5\,N$

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