Force (F) and density (d) are related as F, = ,frac{alpha }{{beta , + ,sqrt d }} then dimension of alpha are

Q: Force $(F)$ and density $(d)$ are related as $F\, = \,\frac{\alpha }{{\beta \, + \,\sqrt d }}$ then dimension of $\alpha $ are

a $[\mathrm{B}]=[\sqrt{\mathrm{d}}]=\left[\mathrm{M}^{1 / 2} \mathrm{L}^{-3 / 2}\right]$ $\Rightarrow\left[\mathrm{M}^{1} \mathrm{L}^{1} \mathrm{T}^{-2}\right]=\frac{[\alpha]}{\left[\mathrm{M}^{1 / 2} \mathrm{L}^{-3 / 2}\right]}$ $[\alpha]=\left[M^{3 / 2} L^{-1 / 2} T^{-2}\right]$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

Force $(F)$ and density $(d)$ are related as $F\, = \,\frac{\alpha }{{\beta \, + \,\sqrt d }}$ then dimension of $\alpha $ are

A$[{M^{3/2}}\,{L^{ - 1/2}}\,{T^{ - 2}}]$
B$[{M^{3/2}}\,{L^{ 1/2}}\,{T^{ 2}}]$
C$[{M^{3/2}}\,{L^{ - 1/2}}\,{T^{2}}]$
D$[{M^{-3/2}}\,{L^{ - 1/2}}\,{T^{ 2}}]$

Medium

STD 11 Science
JEE
STD 11 - 1. units,dimensions and measurement
Physics

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Download App

Download our appand get started for free

Similar Questions

Download our app
and get started for free