MCQ
Formaldehyde and formic acid can be distinguished using
- ATollen's reagent
- BFehling solution
- CFerric chloride
- ✓Sodium bicarbonate
✓
Answer
Correct option: D.
Sodium bicarbonate
d
(d)$HCOOH + NaHC{O_3} \to HCOONa + {H_2}O + C{O_2}$
$HCHO + NaHC{O_3} \to {\rm{No}}\,\,{\rm{reaction}}$
(d)$HCOOH + NaHC{O_3} \to HCOONa + {H_2}O + C{O_2}$
$HCHO + NaHC{O_3} \to {\rm{No}}\,\,{\rm{reaction}}$
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