Question
Formulate a cell from the following electrode reactions :
$ A u _{( aq )}^{3+}+ 3 e ^{-} \longrightarrow A u _{( s )}$
$M g _{( s )} \longrightarrow M g _{( aq )}^{2+}+2 e ^{-}$

Answer

An electrochemical cell from above electrode reactions is,
$ Au _{( aq )}^{3+}+3 e ^{-} \longrightarrow Au _{( s )}$
$\text { (Cathode reduction reaction) }$
$Mg _{( s )} \longrightarrow Mg _{\text {(aq) }}^{2+}+2 e ^{-}$
$\text { (Anode oxidation reaction) }$
$Mg _{( s )}\left| Mg _{( aq )}^{2+} 1 M \right|\left| Au _{\text {(aq) }}^{3+} 1 M \right| Au$

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